Question 1:
What is meant by momentum and conservation of momentum?
Answer:
Mementum (p) is product of the mass (m) of an object and its velocity (v).
p = mv
The Principle of Conservation of Momentum states that the total momentum before collision is equal to the total momentum after collision if no external force is acting on it.
What is meant by momentum and conservation of momentum?
Answer:
Mementum (p) is product of the mass (m) of an object and its velocity (v).
p = mv
The Principle of Conservation of Momentum states that the total momentum before collision is equal to the total momentum after collision if no external force is acting on it.
Question 2:
A lorry of mass 1 000 kg moves at a velocity of 5.0 m s–1. It collides with a car of mass 800 kg moving at a velocity of 2.0 m s–1 in the same direction. If the lorry moves at a velocity of 3.4 m s–1 in the same direction aft er the collision, calculate the velocity of the car.
Answer:
$$ \begin{aligned} m_1 u_1+m_2 u_2 & =m_1 v_1+m_2 v_2 \\ 1000(5.0)+800(2.0) & =1000(3.4)+800\left(v_2\right) \\ 5000+1600 & =3400+800 v_2 \\ 800 v_2 & =5000+1600-3400 \\ 800 v_2 & =3200 \\ v_2 & =\frac{3200}{800} \\ v_2 & =4 \mathrm{~ms}^{-1} \end{aligned} $$
A lorry of mass 1 000 kg moves at a velocity of 5.0 m s–1. It collides with a car of mass 800 kg moving at a velocity of 2.0 m s–1 in the same direction. If the lorry moves at a velocity of 3.4 m s–1 in the same direction aft er the collision, calculate the velocity of the car.
Answer:
$$ \begin{aligned} m_1 u_1+m_2 u_2 & =m_1 v_1+m_2 v_2 \\ 1000(5.0)+800(2.0) & =1000(3.4)+800\left(v_2\right) \\ 5000+1600 & =3400+800 v_2 \\ 800 v_2 & =5000+1600-3400 \\ 800 v_2 & =3200 \\ v_2 & =\frac{3200}{800} \\ v_2 & =4 \mathrm{~ms}^{-1} \end{aligned} $$