Question 1:
State Newton’s Universal Law of Gravitation.
Answer:
Newton’s Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of the masses of both bodies and inversely proportional to the square of the distance between the centres of the two bodies.
State Newton’s Universal Law of Gravitation.
Answer:
Newton’s Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of the masses of both bodies and inversely proportional to the square of the distance between the centres of the two bodies.
Question 2:
State two factors which influence the magnitude of the gravitational force between two bodies.
Answer:
Factors which influence the magnitude of the gravitational force between two bodies:
1. mass of the bodies
2. distance between the bodies
State two factors which influence the magnitude of the gravitational force between two bodies.
Answer:
Factors which influence the magnitude of the gravitational force between two bodies:
1. mass of the bodies
2. distance between the bodies
Question 3:
A piece of space junk of mass 24 kg is at a distance of 7.00 × 106 m from the centre of the Earth. What is the gravitational force between the space junk and the Earth?
[G = 6.67 × 10–11 N m2 kg–2, mass of the Earth = 5.97 × 1024 kg]
Answer:
$$ \begin{aligned} m & =24 \mathrm{~kg} \\ r & =7.00 \times 10^6 \mathrm{~m} \\ G & =6.67 \times 10^{-11} \mathrm{Nm}^2 \mathrm{~kg}^{-2} \\ M_E & =5.97 \times 10^{24} \mathrm{~kg} \\ F & =? \end{aligned} $$
$$ \begin{aligned} & F=\frac{G M_1 m_2}{r^2} \\ & F=\frac{\left(6.67 \times 10^{-11}\right) \times\left(5.97 \times 10^{24}\right) \times 24}{\left(7.00 \times 10^6\right)^2} \\ & F=195.04 \mathrm{~N} \end{aligned} $$
A piece of space junk of mass 24 kg is at a distance of 7.00 × 106 m from the centre of the Earth. What is the gravitational force between the space junk and the Earth?
[G = 6.67 × 10–11 N m2 kg–2, mass of the Earth = 5.97 × 1024 kg]
Answer:
$$ \begin{aligned} m & =24 \mathrm{~kg} \\ r & =7.00 \times 10^6 \mathrm{~m} \\ G & =6.67 \times 10^{-11} \mathrm{Nm}^2 \mathrm{~kg}^{-2} \\ M_E & =5.97 \times 10^{24} \mathrm{~kg} \\ F & =? \end{aligned} $$
$$ \begin{aligned} & F=\frac{G M_1 m_2}{r^2} \\ & F=\frac{\left(6.67 \times 10^{-11}\right) \times\left(5.97 \times 10^{24}\right) \times 24}{\left(7.00 \times 10^6\right)^2} \\ & F=195.04 \mathrm{~N} \end{aligned} $$