Formative Practice 1.2 – Physics Form 5 Chapter 1 (Force and Motion II)
Question 1:Resolve the following forces into horizontal component and vertical component. Answer:(a)$$ \begin{aligned} & F_x \equiv 70 \cos 42^{\circ} \\ & F_x \equiv 52.02 \mathrm{~N} \end{aligned} $$$$ \begin{aligned} & F_y=70 \sin 42^{\circ} \\ & F_y=46.84 \mathrm{~N} \end{aligned} $$(b)$$ \begin{aligned} F_x & =90 \cos 64^{\circ} \\ F_x & \equiv 39.45 \mathrm{~N} \end{aligned} $$$$ \begin{aligned} & E_y … Read more