Summative Practice 3 (Question 1 – 3) – Physics Form 5 Chapter 3 (Electricity)

Question 1:Figure 1 shows a filament lamp. Why does a coiled filament produce a brighter light? Answer:– The filament lamps require high resistance to produce light.– The coiled filament causes the wire length to increase.– The resistance is directly proportional to the length of the wire.– The longer the filament wire, the higher the resistance.– … Read more

Efficiency of Electrical Appliance

Efficiency of Electrical Appliance The efficiency of an electrical appliance is given by the following equation Normally, the efficiency of an electrical appliance is less than 100% due to the energy lost as heat and the work done against friction in a machine. Example 1A lamp is marked “240V, 50W”. If it produces a light … Read more

Power Rating

Power Rating Figure above is an example of power rating label. An electrical appliance which is marked 240V, 1200W means that the electrical appliance will consume 1200J of energy in every second if the potential difference across it is 240V. ExampleA bulb rated 240V/80W is operated from a 120V power source. Find the resistance and … Read more

Sum of the Power

In a circuit of any connection (series or parallel), the power dissipated in the whole circuit is equal to the sum of the power dissipated in each of the individual resistor. Example 1:2 identical bulb of resistance 3Ω is connected to an e.m.f. of 12V. Find the power dissipated in the circuit ifa. the bulb … Read more